Parallelogram ABCD has vertices at A (0, 0), B (3, 6), C (5, 5), and D (2, -1).
Which conclusion can be made?
O ABL BC; therefore, ABCD is a square.
O ABL BC; therefore, ABCD is a rectangle.
O AB = BC; therefore, ABCD is a square.
O AB = BC; therefore, ABCD is a rhombus.

Parallelogram ABCD has vertices at A 0 0 B 3 6 C 5 5 and D 2 1 Which conclusion can be made O ABL BC therefore ABCD is a square O ABL BC therefore ABCD is a rec class=