contestada

You are shown \angle CDE∠CDE below whose measure is 98^{\circ}.98

. Draw an angle bisector of \angle CDE∠CDE by clicking a dragging a ray out from the vertex at D.D.
Click and drag to draw a ray from the yellow dot.
To redraw, click and drag from the yellow dot again.

\text{m}\angle CDE= \text{m}\angle EDFm∠CDE=m∠EDF
\text{m}\angle EDF=\frac{1}{2}\left(\text{m}\angle CDE\right)m∠EDF=
2
1

(m∠CDE)
\text{m}\angle CDE= \text{m}\angle CDFm∠CDE=m∠CDF
\text{m}\angle CDF= 2\left(\text{m}\angle EDF\right)m∠CDF=2(m∠EDF)

Respuesta :