Given: sin(A-B) = sinA cosB-cosA sinB;
sin(90°) = 1
cos(90°) = 0
Prove: sin(90* - 2) = cos(x)
Statements:
1.sin(A - B) = sinA cosB - cosA sinB
2. Let A = 90° and B =
3.sin(90 - 2) = sin(90°) cos(z) - cos(90°) sin(x)
4. sin(90) = 1 cos(x) -0. sin (2)
5. sin(90 - 2) = 1. cos(z) - 0
6. sin(902) = 1. cos (2)
7.sin(90° - 2) = cos(x)
From this derivation, which expression is equivalent to sin(y +15°)?
O cos (y + 15°)
Ocos (15-y)
O cos (y +75)
cos (75* - y)