We are given that BD⎯⎯⎯⎯⎯
bisects AC⎯⎯⎯⎯⎯
at point E
and ∠BAE≅∠DCE.
Because BD⎯⎯⎯⎯⎯
bisects AC⎯⎯⎯⎯⎯
at point E,
we know that AE⎯⎯⎯⎯⎯≅CE⎯⎯⎯⎯⎯
by the , 1 of 3..
By the , 2 of 3., ∠AEB≅∠CED.
Therefore, △ABE≅△CDE
by , 3 of 3..
