We are given that BD⎯⎯⎯⎯⎯
bisects AC⎯⎯⎯⎯⎯
at point E
and ∠BAE≅∠DCE.

Because BD⎯⎯⎯⎯⎯
bisects AC⎯⎯⎯⎯⎯
at point E,
we know that AE⎯⎯⎯⎯⎯≅CE⎯⎯⎯⎯⎯
by the , 1 of 3..
By the , 2 of 3., ∠AEB≅∠CED.

Therefore, △ABE≅△CDE
by , 3 of 3..

We are given that BD bisects AC at point E and BAEDCE Because BD bisects AC at point E we know that AECE by the 1 of 3 By the 2 of 3 AEBCED Therefore ABECDE by class=