Let us assume that Cd(OH)2(s) is completely insoluble, which signifies that the precipitation reaction with NaOH(aq) (presented in the transition) would go to completion.

Cd2+(aq)+2NaOH(aq) → Cd(OH)2(s)+2Na+(aq)

If you had a 0.300 L solution containing 0.0220 M of Cd2+(aq) , and you wished to add enough 1.25 M NaOH(aq) to precipitate all of the metal, what is the minimum amount of the NaOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH−(aq) for the precipitation.