Let A = [ -3 4 6 -8 ] and b = [b ₁ b₂] Show that the equation Ax=b does not have a solution for some choices of b, and describe the set of all b for which Ax = b does have a solution.
How can it be shown that the equation Ax=b does not have a solution for some choices of b?
5. A. Row reduce the augmented matrix [ A b ] to demonstrate that [ A b ] has a pivot position in every row.
B. Row reduce the matrix A to demonstrate that A does not have a pivot position in every row.
C. Find a vector b for which the solution to Ax=b is the identity vector.
D. Find a vector x for which Ax=b is the identity vector.
E. Row reduce the matrix A to demonstrate that A} has a pivot position in every row.
Describe the set of all b for which Ax=b does have a solution.
The set of all b for which Ax=b does have a solution is the set of solutions to the equation 0=0b₁+b₂.
(Type an integer or a decimal.)