How many moles of sulfuric acid (H₂SO4) are needed to react completely with 6.8 moles of lithium hydroxide (LIOH)?
2LIOH + H₂SO4 → Li2SO4 + 2H₂O
O 3.4 mol H₂SO4
O 6.8 mol H₂SO4
O 10.2 mol H₂SO4
O 13.6 mol H₂SO4