Calculate K at 298 K for the following reaction: SrSO4(s) <--> Sr2+(aq) + SO42-(aq) SCIENTIFIC NOTATION PLEASE...thank you
. Comments : the answer K = 3.48 x 10^-7was wrong,it said HInt: For any state function (G, H, or S) the change in the state function, F, for a reaction can be calculated from Delta F rxn= (sideways M)n x delta F (products) minus (sideways M) n x delta F (reactants), when n are the stoichiometric coefficients from the balanced chemical equation. Use this expression to calculate Delta G rxn. Use the expression that relates change in fuel energy of a reaction, Delta G rxn, to the equilibrium constant K. p.s. (the ^-7 power part was correct).
I still get 2 more chances.
comment from chegg:You have not given the standard free energies(dG0) of the components. If you have the values simply calculate dG0 of the reaction, dG0 = ? dG0 value of products -? dG0 value of reactants Here it will be, dG0 = (dG0SO42- + dG0Sr2+) - (dG0SrSO4) Then calculate, K according to the equation, dG0 = -RTlnK
My comment: it did not give me values... help?