Suppose a discrete random variable Y has positive value of p.d.f. p(y) for y = -1,0,1 and p(y) = 0 elsewhere. If p(0) = 0.25 and the expected value E(Y) = 0.25, then find the values of p(-1) and p(1). Suppose a discrete random variable Y has a Geometric probability distribution with probability of success p (>0). Its p.d.f.p(y) is defined as P(Y = y) = p(y) = p (1 - p)y-1 for y 1, 2, 3, ... Verify that the sum of probabilities when the values of random variable Y are even integers only is 10. That is to find p(2) + p(4) +p(6) + ... 2-p