Determine whether the given function is a solution to the given differential equation. 0=4e3-2e²¹ de 0 +30=-3e²1 dt The function 8=4e3-2e²1 de substituted for and dt a solution to the differential equation is substituted for d²0 de -0- dt² dt +30= -3e²¹, because when 4e3-2 e21 is substituted for is d²e the two sides of the differential equation dt² equivalent on any intervals of t