Use variation of parameters to find a general solution to the differential equation given that the functions y₁ and y₂ are linearly independent solutions to the corresponding homogeneous equation for t> 0. ty'' +(3t-1)y' - 3y = 8t² e - 3t. y₁ =3t-1, y₂ = e - 3t A general solution is y(t)= c₁ (3t-1) + C₂ € 1-376 - 3t - 3t