In this problem you will use variation of parameters to solve the nonhomogeneous equation t2y′′+ty′−9y=−(2t3+3t2) A. Plug y=tn into the associated homogeneous equation (with " 0 * instead of " −(2t3+3t2) ") to get an equation with (Note: Do not cancel out the t, or webwork won't accept your answerl) B. Solve the equation above for n (use t=0 to cancel out the t ). You should get two values for n, which give two fundamental solutions of the form y=tn. y1​W(y1​,y2​)​==​y2​=​ C. To use variation of parameters, the linear differential equation must be written in standard form y′′+py′+qy=g. What is the function g ? g(t)= D. Compute the following integrals. ∫Wy1​g​dt=∫Wy2​g​dt=​ E. Write the general solution. (Use c1 and c2 for c1​ and c2​ ). y=ctt∧(−3)+c2t∧3+(t∧3)/18)+(t∧2/10)+t∧2/2)−(t∧(3)int/3)) If you don't get this in 3 tries, you can get a hint to help you find the fundamental solutions.