Suppose that a 4×4 matrix A has eigenvalues λ1​=1,λ2​=−3,λ3​=4, and λ4​=−4. Use the following method to find det (A) If p(λ)=det(λI−A)=λn+c1​λn−1+⋯+cn​ So, on setting λ=0, we obtain that det(−A)=cn​ or det(A)=(−1)ncn​ det(A)=