The functions y 1
​
=e 4x
and y 2
​
=e −4x
are both solutions for the homogeneous DE: y ′′
−16y=0 Then, the general solution of nonhomogeneous DE y ′′
−16y=32x−16 is Select one: y=c 1
​
e 4x
+c 2
​
e −4x
−2x+1 y=c 1
​
e 4x
+c 2
​
e −4x
−2x−1 y=c 1
​
e 4x
+c 2
​
e −4x
+2x−1 None of these. y=c 1
​
e 4x
+c 2
​
e −4x
+2x+1