Determine the enthalpy of reaction for 2CH4(g) > C2H4(g) + 2H2(g) using the equations: 2C2H6(g) + 702(g) > 4C02(g) + 6H20(1) AH° = -3120.8 kJ/mol CHA(g) + 202(g) > C02(g) + 2H20(1) ДН° = -890.3 kJ/mol C2H4(g) + H2(g) > C2H6(g) ДН° = -136.3 kJ/mol H2 + ½02(g) > H20(1) ДН° = -285.8 kJ mol|