lover4844 lover4844 07-01-2024 Mathematics contestada For random variables X1 and X2 distributed identically as X1 ∼ Ber(p) ∼ X2, what is E(Y1) and E(Y2)?Options:A. E(Y1) = p², E(Y2) = p(1 - p)B. E(Y1) = p, E(Y2) = p²C. E(Y1) = p², E(Y2) = pD. E(Y1) = p(1 - p), E(Y2) = p²