linlin9766 linlin9766

08-01-2024
Mathematics

contestada

Solve for x. Assume the equation has a solution for x.
[3 = 5ax + 3x = bx]
a) (x = 3/5a + 3b)
b) (x = 3/5a - 3b)
c) (x = 3/3b - 5a)
d) (x = 3/5a + bx)

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