A student performs an experiment to determine the Young’s modulus of a wire exactly 2 m long by Searle’s method. In a particular reading, he measures the extension in the length of the wire to be 0.8mm with an uncertainty of ±0.05mm
at a load of exactly 1.0 kg . He also measures the diameter of the wire to be 0.4mm with an uncertainty of ±0.01mm . The young’s Modulus obtained from the reading is: (Given Young’s modulus of a wire is given by Y=Fl/Ae, where F
is the force applied on the wire, l is the length of the wire, A
is the area of cross section of the wire and e is the elongation produced in the wire due to the load. Take g=9.8m/s² )
(A) (2±0.3)×10¹¹N/m²

(B) (2±0.2)×10¹¹N/m²

(C) (2±0.1)×10¹¹N/m²

(D) (2±0.5)×10¹¹N/m²