xphamjenny4475 xphamjenny4475 09-01-2024 Mathematics contestada If the system of linear equationsx−2y+kz=12x+y+z=23x−y−kz=3has a solution (x,y,z),z≠=0, then (x.y) lies on the straight line whose equation is :A. 3x−4y−1=0B. 4x−3y−4=0C. 4x−3y−1=0D. 3x−4y−4=0