Choose the loop that is equivalent to this loop.
int n = 1;
double x = 0;
double s;
do
{
s = 1.0 / (n * n);
x = x + s;
n++;
}
while (s > 0.01);
a) double x = 0;
double s = 1;
for (int k = 1; s > 0.01; k++) {
s = 1.0 / (k * k);
x = x + s; }
b) double x = 0;
double s = 1;
for (int k = 1; k < 100; k++) {
s = 1.0 / (k * k);
x = x + s; }
c) double x = 0;
double s = 1;
int k = 10;
while (s > 0.01) {
s = 1.0 / (k * k);
x = x + s;
k++; }
d) double x = 0;
double s = 10;
int k = 1;
while (s > 0.01) {
s = 1.0 / (k * k);
x = x + s;
k++;