Let Q1, Q2, Q3 be constants so that R (4.8x2 +6.2x+15) dx = Q1x3 +Q2x2 +Q3x+C, where C is a constant of integration. Let Q = ln(3 + |Q1| + 2|Q2| + 3|Q3|). Then T = 5sin2(100Q)satisfies:—(A)0≤T <1. —(B)1≤T <2. —(C)2≤T <3. —(D) 3≤T <4. —(E)4≤T ≤5.