CS2 and Cl2 react according to the follow-
ing equation
CS2(g) + 3 Cl2(g) S₂Cl2(g) + CCl4(g).
When 2.0 mole of CS2 and 4.00 moles of
Cl₂ are placed in a 2.00 liter container and
allowed to come to equilibrium, the mixture
is found to contain 0.50 moles of CCl4. What
is the amount of Cl2 at equilibrium?
1. 1.50 mol Cl₂
2. 0.50 mol Cl2
3. 2.50 mol Cl₂
4. 2.75 mol Cl2
5. 0.25 mol Cl2
6. 0.75 mol Cl₂2
7. 2.25 mol Cl₂