How many grams of water would be formed from 96.0 g NH in a reaction represented by the balanced equation below. Show how to set up the calculation using dimensional analysis by selecting the correct factors from the menu. Then select the correct answer from the answer menu.
4 NH 3(9) + 3 02(g) → 2 N2(g) + 6H20(1)
96.0 g NH,
1 mol NH
96.0 g NH,
Please put an answer in each box.
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