penguinsydney4164 penguinsydney4164
  • 15-02-2024
  • Mathematics
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What is the solution to the equation 2cos(2x)cos(x)-2sin(2x)sin(x)=-√2?

A) 2cos(2x)cos(x)-2sin(2x)sin(x)=-√2
B) cos(2x)cos(x)-sin(2x)sin(x)=-√2
C) cos(2x)cos(x)-sin(2x)sin(x)=√2
D) cos(2x)cos(x)-sin(2x)sin(x)=√2

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