ScienceNerd2631 ScienceNerd2631

15-02-2024
Physics

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A particle is moving along a straight line and its velocity is given by v(t) = t^2e^(-t) feet per second after t seconds. What is the integral of t^2e^(-t)dv from 0 to 5?

A) 25e^(-5) - 2e^(-5)
B) 25e^(-5) + 2e^(-5)
C) -25e^(-5) + 2e^(-5)
D) -25e^(-5) - 2e^(-5)

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