What is the stopping distance in feet for a car traveling at x miles per hour on wet level pavement, according to the equation D(x) = (1/4)x^2 + (27/2)x? If a driver can only see 200 feet ahead on a curve, what is the stopping distance in feet?

A) (1/4)x^2 + (27/2)x
B) 200
C) (1/4)(200)^2 + (27/2)(200)
D) None of the above