In a titration, a 25.00 mL sample of HCI required 19.07 mL of a 0.7971 M NaOH solution to reach the endpoint. Calculate concentration of HCI. (M=mol/L; mol=MxV)
HCl(aq) + NaOH(aq) → H₂O(l) + NaCl(aq)
Answer to 4 sig figs (0._____). Do not include unit, M.