A student completed the experiment in part 3 and found the following information. Use the information provided to solve for the specific heat capacity of the cylinder.
Mass of H2O added (d = 1.00 g/mL) 31.4 g
Specific Heat of Water (c) 4.184 J/(g °C)
Change in Temperature of water (ΔT) 65.0 °C
Mass of cylinder 38.0904 g
Change in Temperature of cylinder -10.5 °C