Equilibrium constant expression and value for the reaction BaF₂ ⇌ Ba²⁺ + 2F⁻:
a) Kc = [Ba²⁺][F⁻]², Kc = 1.6 x 10⁻⁴
b) Kc = [Ba²⁺][F⁻], Kc = 3.2 x 10⁻⁵
c) Kc = [BaF₂], Kc = 5.0 x 10⁻³
d) Kc = [Ba²⁺][F⁻]², Kc = 3.6 x 10⁻⁴