In a small town of 5,832 people, the mayor wants to determine if there is a difference in the proportion of voters
ages 18-30 who would support an increase in the food tax, and the proportion of voters
ages 31-40 who would
support an increase in the food tax. An assistant to the mayor surveys 85 randomly chosen
voters ages 18-30,
and finds that 62 support the increase. A random sample of 70 voters ages 31-40 is
also surveyed, and 56
support the increase. Assuming the conditions for inference have been met, what
is the 99% confidence
interval
for the difference in proportions of voters who would support the increase in
the food tax for the different age
groups?
Find the z-table here.
O (0.27-0.20) ±1.96-
(0.73-0.80) ±1.96
O (0.27-0.20) ±2.58
O(0.73-0.80) ±2.58
Mark this and return
0.27(1-0.27)+ 0.20(1-0.20)
85
70
0.73(1-0.73)+ 0.80(1-0.80)
70
85
0.27(1-0.27) 0.20(1-0.20)
70
85
+
0.73(1-0.73) 0.80(1-0.80)
85
70
+