A 500 g particle has velocity vx = 1.0 m/s at t = -2 s. Force Fx=(4−t2)N, where t is in s, is exerted is exerted on the particle between t=−2 and t = 2 s. This force increases from 0 N at t = -2 s to 4 N at t = 0 s and then back to 0 N at t = 2 s
What is the particle’s velocity at t = 2 s?