Consider the cell reaction: Pb2 + 2e- -> Pb. Using any data sheet, find a metal M such that the lead half-cell is the anode, the M half-cell is the cathode, and the overall reaction is:
a) M + Pb2+ -> M2+ + Pb
b) M + 2Pb2+ -> 2M2+ + 2Pb
c) M + 2Pb2+ -> 2M + 2Pb
d) M + Pb2+ -> M + Pb