In a population of 100 sweet pea plants
- 45 are homozygous dominant (TT)
- 35 are heterozygous (Tt) and
- 20 are homozygous recessive (tt)
so this population has (45 x 2) + 35= ___ dominant alleles and (20 x 2) + 35 =___ recessive alleles
the frequency of the dominant alleles T is given by
[tex]p = \frac{?}{ 200} = [/tex]

the frequency of the recessive alleles T is given by
[tex]q = \frac{?}{200} = [/tex]

the frequency of the homozygous dominant genotype TT is given by
[tex] {p}^{2} = {0.625}^{2} = [/tex]

the frequency of the heterozygous genotype TT is given by
[tex]2pq = 2(0.625)(0.375) = [/tex]

the frequency of the homozygous recessive genotype TT is given by
[tex] {q}^{2} = {0.325}^{2} = [/tex]


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