The molecular mass of a pure monoprotic acid is known to be 192.1 g/mol. You have a mixture of that acid with NaCl (no acid-base properties). When you titrate a 0.622 g sample of that mixture with 0.1014 M NaOH, the titration requires 21.52 mL of titrant. What was the percentage by mass of the acid in the mixture? Calculate the percentage to the 0.1% place, e.g., 48.3%, not just 48%. Enter the numerical value of the percentage, without the % symbol, e.g., enter 48.3% as 48.3. Note: Mixtures are expected to be in the 10 - 90% range.