Explain how IMFs can be used to explain solubility in a solvent, whether it is in heptane or in water.
a) IMFs play a significant role in determining solubility by interacting with solute molecules.
b) IMFs have minimal impact on solubility, which is primarily determined by the chemical structure of the solvent.
c) IMFs are irrelevant in determining solubility; it is solely based on the temperature and pressure conditions.
d) IMFs directly influence solubility only in water, not in other solvents like heptane.