A proton moves through a uniform magnetic field given by B= (10i ? 20j + 30k) mT. At time t1, the proton has a velocity given by v= vx*i + vy*j + (2.4 km/s)*k and the magnetic force on the proton is FsubB = (4.1* 10-17 N)i + (2.1* 10-17 N)j. At that instant, what is vx? At that instant, what is vy?