Using Hess’s Law, determine the enthalpy (ΔH) of the reaction given below:
2N₂ + 2O₂ → 4NO
Given are the two equations with known enthalpies:
4NH₃ + 5O₂ → 4NO + 6H₂O ΔH = −1170 kJ
2N₂ + 6H₂O → 4NH₃ + 3O₂ ΔH = +1530 kJ
A) 2700 KJ
B) +360.0 KJ
C) -360.0 KJ
D) -2700 KJ