Respuesta :
You should use 2/9 of a pint of the 1% milk and 1/9 of a pint of the 4% milk.
Let x be the amount of 1% milk used. 1% = 1/100 = 0.01; this gives us 0.01x to represent this.
We know that we will use the 4% milk to make up the rest of the 1/3 pint; this gives us 0.04(1/3-x).
Together, they will make 1/3 pint of 2% milk, or 0.02(1/3)
This gives us the equation
0.01x+0.04(1/3-x) = 0.02(1/3)
Multiplying, we have
0.01x+0.04/3-0.04x = 0.02/3
We can multiply everything by 3 to eliminate the fractions:
0.01x*3 + 0.04 - 0.04x*3 = 0.02
0.03x + 0.04 - 0.12x = 0.02
Combining like terms, we have
-0.09x + 0.04 = 0.02
Subtract 0.04 from both sides:
-0.09x + 0.04 - 0.04 = 0.02 - 0.04
-0.09x = -0.02
Divide both sides by -0.09:
-0.09x/-0.09 = -0.02/-0.09
This gives us x = 2/9, so we will use 2/9 of a pint of the 1% milk.
1/3 - 2/9 = 3/9 - 2/9 = 1/9; we will use 1/9 of a pint of the 4% milk.
Let x be the amount of 1% milk used. 1% = 1/100 = 0.01; this gives us 0.01x to represent this.
We know that we will use the 4% milk to make up the rest of the 1/3 pint; this gives us 0.04(1/3-x).
Together, they will make 1/3 pint of 2% milk, or 0.02(1/3)
This gives us the equation
0.01x+0.04(1/3-x) = 0.02(1/3)
Multiplying, we have
0.01x+0.04/3-0.04x = 0.02/3
We can multiply everything by 3 to eliminate the fractions:
0.01x*3 + 0.04 - 0.04x*3 = 0.02
0.03x + 0.04 - 0.12x = 0.02
Combining like terms, we have
-0.09x + 0.04 = 0.02
Subtract 0.04 from both sides:
-0.09x + 0.04 - 0.04 = 0.02 - 0.04
-0.09x = -0.02
Divide both sides by -0.09:
-0.09x/-0.09 = -0.02/-0.09
This gives us x = 2/9, so we will use 2/9 of a pint of the 1% milk.
1/3 - 2/9 = 3/9 - 2/9 = 1/9; we will use 1/9 of a pint of the 4% milk.
The double lathe milk with 2 percent fat concentration, is made by
considering the concentration and amount of each constituent.
The amount of each type of milk to be used in the [tex]\dfrac{1}{3}[/tex] pint of double lathe
are;
- [tex]\dfrac{2}{9}[/tex] pint of the 1 percent fat milk and [tex]\dfrac{1}{9}[/tex] pint of the 4 percent fat milk.
Reasons:
Let x represent the amount of the milk that contains 1 percent fat in the
volume of the 2 percent fat milk.
Therefore, we have;
The amount of the 4 percent fat milk to be used = [tex]\dfrac{1}{3} - x[/tex]
[tex]Amount \ of \ fat = \dfrac{1}{100} \times x + \dfrac{4}{100} \times \left (\dfrac{1}{3} - x\right) = \dfrac{2}{100} \times \dfrac{1}{3} = \dfrac{2}{300}[/tex]
[tex]\dfrac{1}{100} \times x + \dfrac{4}{100} \times \left (\dfrac{1}{3} - x\right) = \dfrac{4 - 9 \cdot x}{300} = \dfrac{2}{300}[/tex]
Therefore;
4 - 9·x = 2
4 - 2 = 9·x
[tex]x = \dfrac{2}{9}[/tex]
The amount of the 1 percent fat milk to be used for the double lathe, x = [tex]\dfrac{2}{9}[/tex]
of a pint.
The amount of the 4 percent fat milk to be used for the double lathe = [tex]\dfrac{1}{3} - x[/tex]
Therefore;
The mount of the 4 percent fat milk = [tex]\dfrac{1}{3} - \dfrac{2}{9} =\dfrac{1}{9}[/tex]
The amount of the 4 percent fat milk to be used for the double lathe = [tex]\dfrac{1}{9}[/tex]
pint.
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https://brainly.com/question/13220698
