The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heights of trees at The Grow Station in feet : 9, 11, 6, 12, 7 Which statements are true regarding the measures of center and variability of these data sets? Check all that apply. The mean of tree heights at Yard Works is 7 feet. The mean of tree heights at Yard Works is 8 feet. The mean of tree heights at The Grow Station is 9 feet. The mean of tree heights at The Grow Station is 10 feet. The mean absolute deviations of the tree heights at both yards is 2. The mean absolute deviations of the tree heights at both yards is 3. Mark this and return Save and Exit

The mean of tree heights at Yard Works is 8 feet.
The mean of tree heights at The Grow Station is 9 feet.
The mean absolute deviations of the tree heights at both yards is 2.

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eudora eudora · Answer 2 · 2019-01-20T17:22:24+01:00

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

= 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.