Respuesta :

choixongdong
(-6,5) and (-3,-3) 
slope = (5+3)/(-6 + 3) = 8/-3 = -8/3

y = mx + b
b = y - mx
b = -3 - (-8/3)(-3)
b = -3 - 8
b = -11

equation
y = -8/3 x - 11

hope it helps

The equation of the line passing through the points (-6,5) and (-3,-3) will be y = -(8/3)x - 11.

What is the equation of a line passing through two points?

Let the equation of the line pass through (x₁, y₁) and (x₂, y₂).

Then the equation of the line is given as,

[tex]\rm (y - y_2) = \left (\dfrac{y_2 - y_1}{x_2 - x_1} \right ) (x - x_2)[/tex]

The points are given below.

(-6,5) and (-3,-3)

Then the equation of the line passing through the points (-6,5) and (-3,-3) will be

[tex]\rm (y + 3) = \left (\dfrac{-3-5}{-3+6} \right ) (x + 3)[/tex]

Simplify the equation, then the equation of the line will be

y + 3 = -(8/3)(x + 3)

y = -(8/3)x - 8 - 3

y = -(8/3)x - 11

Then the equation of the line passing through the points (-6,5) and (-3,-3) will be y = -(8/3)x - 11.

More about the line passing through two points link is given below.

https://brainly.com/question/12740817

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