What additional information can be used to prove ΔFEG ≅ ΔFQG by SAS?

Answer: ∠EFG=∠QFG
Step-by-step explanation:
In the given picture we have two triangles ΔFEG and ΔFQG in which EF=FQ
and GF=GF [ by reflexive property].
To apply SAS postulate we need included angle of sides EF, GF and FQ, GF.
Therefore, the additional information can be used to prove ΔFEG ≅ ΔFQG is given by :-
∠EFG=∠QFG