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A ball is thrown from 4 feet off the ground with a vertical velocity of 30 feet per second. Is the ball at its maximum height after 1 second? In two or more complete sentences, explain how you know whether or not the ball is at its maximum height.

Respuesta :

jushmk
At maximum height, the velocity of the ball is zero. In other words, the ball is momentarily at rest at maximum height before  it starts falling down.
The following equation explains this scenario:

v=u-gt, but v = 0
Therefore,
0=u-gt => u = gt, u = 30 ft/s, g = 9.81 m/s^2 = 32.174 ft/s^2

Substituting;
t = u/g = 30/32.172 = 0.9324 seconds ≈ 1 second
yakubuemmanuel432

Answer:

0.9375sec.

Step-by-step explanation:

Using the motion formula: V= u - gt

At Max. Height, V=0, taking t=32ft/sec^2

Thus: 0 = 30 - 32t

32t = 30

t=30/32

t= 0.9375sec

Therefore,

it will take 0.9375seconds which is less than 1 second to reach maximum height, then the ball starts descending. Just after 1 sec, ball is below its maximum height and in downward motion.