We have the following functions:
f (x) = -3x ^ 4 - 14
g (x) = -x ^ 3 + 2f
Deriving both functions we have:
f '(x) = -12x ^ 3
g '(x) = -3x ^ 2
We equal zero and clear x:
f '(x) = -12x ^ 3 = 0 ----> x = 0
g '(x) = -3x ^ 2 = 0 -----> x = 0
Substituting x = 0 in the given equations:
f (0) = -3 (0) ^ 4 - 14 = -14
g (0) = - (0) ^ 3 + 2 = 2
Answer:
the largest maximum y-value is:
B.g (x)
