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The chemical equation below shows the decomposition of nitrogen triiodide (NI3) into nitrogen (N2) and iodine (I2). 2NI3 mc030-1.jpg N2 + 3I2 The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?

Respuesta :

The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?


0.0136 

Answer:

0.0135 moles of iodine will be formed.

Explanation:

[tex]2NI_3\rightarrow N_2+3I_2[/tex]

Moles of nitrogen triiodide =[tex]\frac{3.58 g}{394.71 g/mol}=0.0090 mol[/tex]

According to reaction 2 moles of nitrogen triiodide gives 3 moles of iodione gas.

Then 0.0090 mol of nitrogen triiodide will give:

[tex]\frac{3}{2}\times 0.0090 mol=0.0135 mol[/tex]

0.0135 moles of iodine will be formed.

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