Let the event to win the first game is F and to win the second game is S.
This question is from conditional probability and hence we use the below formula.
[tex]P(S/F)=\frac{P(F and S) }{P(F)}[/tex]
Now, we have been given that
[tex]P(F and S)=0.18\\
P(F)=0.60[/tex]
On substituting these given values in the formula, we get
[tex]P(S/F)=\frac{0.18}{0.60} \\
\\
P(S/F)=0.3=30\%[/tex]
Therefore, the probability for winning the second game is 30%
