Answer: The probability of hitting an odd number three times is [tex]3\dfrac{3}{8}[/tex] times more than the probability of hitting an even number 3 times.
Step-by-step explanation:
From the given picture , the total total number of sections in the spinner = 5
Sections having Odd numbers = 3
Sections having Even numbers =2
We know that , [tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]
So , probability of hitting an odd number = [tex]\dfrac{3}{5}[/tex]
Probability of hitting an even number = [tex]\dfrac{2}{5}[/tex]
Since all events are independent of each other ,
So , probability of hitting an odd number three times = [tex](\dfrac{3}{5})^3=\dfrac{27}{125}[/tex]
Probability of hitting an even number three times = [tex](\dfrac{2}{5})^3=\dfrac{8}{125}[/tex]
Divide [tex]\dfrac{27}{125}[/tex] by [tex]\dfrac{8}{125}[/tex] , we get
[tex]\dfrac{27}{125}\div\dfrac{8}{125}\\\\=\dfrac{27}{125}\times\dfrac{125}{8}=\dfrac{27}{8}=3\dfrac{3}{8}[/tex]
Hence, the probability of hitting an odd number three times is [tex]3\dfrac{3}{8}[/tex] times more than the probability of hitting an even number 3 times.
