Suppose you wish to make 0.879 l of 0.250 m silver nitrate by diluting a stock solution of 0.675 m silver nitrate. how many milliliters of the stock solution would you need to use?

Respuesta :

Answer is: 325.5 mL of the stock solution.

c₁(AgNO₃) = 0.675 M.

V₂(AgNO₃) = 0.879 L.
c
₂(AgNO₃) = 0.250 M.
V
₁(AgNO₃) = ?
c
₁ - original concentration of the solution, before it gets diluted.
c
₂ - final concentration of the solution, after dilution.
V
₁ - volume to be diluted.
V
₂ - final volume after dilution.
c
₁ · V₁ = c₂ · V₂.
V
₁(AgNO₃) = c₂ · V₂ ÷ c₁.
V
₁(AgNO₃) = 0.250 M · 0.879 L ÷ 0.675 M.
V
₁(AgNO₃) = 0.325 L · 1000 mL = 325 mL.