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When two molecules of methanol (ch3oh) react with oxygen, they combine with three o2 molecules to form two co2 molecules and four h2o molecules. how many h2o molecules are formed when 66 methanol molecules react?

Respuesta :

[tex]2CH_{3}OH +3O_{2}--\ \textgreater \ 2CO_{2}+4H_{2}O From reaction 2 molecules CH_{3}OH give 4 molecules H_{2}O. [/tex]

[tex] \frac{2 molecules CH_{3}OH}{4 molecules H_{2}O} = \frac{66 molecules CH_{3}OH}{x molecules H_{2}O} x= 4*66/2=132 molecules of H_{2}O[/tex]
adioabiola

The number of water molecules formed when 66 molecules of ethanol react is; 132 molecules of water.

When two molecules of methanol react with oxygen.

  • They combine with three O2 molecules as implied in the question to form CO2 molecules and four H20 molecules.

The reaction between methanol and oxygen is as follows;

  • 2CH3OH + 3O2 --> 2CO2 + 4H2O

According to the equation,

  • 2 molecules of CH3OH = 4 molecules of H2O

Therefore,

  • 66 molecules of CH3OH = x molecules of H2O

In essence, the number of x molecules of water formed when 66 molecules of ethanol react is;

  • x = (66 × 4)/2

  • x = 132 molecules of water.

The number of water molecules formed when 66 molecules of ethanol react is; 132 molecules of water.

Read more:

https://brainly.com/question/1527437

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