Given the equation zn(s) + 2 hcl(aq) → zncl2(aq) + h2(g), what mass of hydrogen gas is produced when 2.8 g zn is reacted with excess aqueous hydrocholric acid?
zn+2hcl»zncl2+h2 108+2(1+35.5)»108+71+2 179.2»179+2 108g of zn gives 2g of h when reacted with excess hcl therefore 2.8g of zn in the same reaction will give 2.8*2/108=0.0518
