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vazquez561209
 i think that's the answer   a^21b^29c^14
The simplified expression is shown below:

[tex]( a^{2} b^{5} c^{3} )^{4} ( a^{3} b^{3} )^{3} ( a^{2} c )^{2} \\ \\ =( a^{8} b^{20} c^{12} )( a^{9} b^{9} )( a^{4} c^{2} ) \\ \\ = a^{(8+9+4)} b^{(20+9)} c^{(12+2)} \\ \\ = a^{21} b^{29} c^{14} [/tex]

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